A network engineer notices that two mesh APs are having problems communicating. After reviewing the current radio configurations, it is noted that one AP is transmitting at 3 mW while the other is transmitting at 60 mW. How many decibels would the 3-mW AP need its power increased to match the 60- mW AP?
A. 8
B. 12
C. 13
D. 20
E. 57
Easiest way here is simply how to get from 3 to 60? Multiply 3 by ten then double it. That is 3 x 10 x 2 = 60.
In dB multiply by 10 = +10dB. Then double + +3 dB. 10 + 3 + 13.
10 + 3 = 13
We need to use the 10db and 3db rules to get from 3mW to 60mW.
10db = 10x, so 3mW + 10db = 30mW
10x more would be too much, so we go to 3db.
3db = 2x, so 30mw + 3db = 60mW
Adding 10db gets you 10x the amount. Adding 3db gets you 2x the amount. Conversely, -10db is 1/10th and -3db is 1/2.
i really would love to have an explanation for this question as i can’t find the result make sense
Fox is right… add his 10dbm + 3dbm = 13db
also
3mw going to 60mw
using 3dB * 2
3mw * 2 = 6mw so we note the first 3dbm
6mw*2 = 12mw so we note the second 3dbm but this time add the previous 3 = 6dbm
12mw*2=24Mw so we note the third 3db + the previous 6dbm = 9dbm
24mw*2= 48mw so we note the fourth 3db + previous 9dbm = 12dbm
But now we cant multiply 48*2 since it will be more than 60mw so we subtract. 60mw -48mw = 2mw which is clode to 1db
so 12 + 1 = 13 dbM
i really would love to have an explanation for this question as i can’t answer