How many decibels would the 3-mW AP need its power increased to match the 60- mW AP?

A network engineer notices that two mesh APs are having problems communicating. After reviewing the current radio configurations, it is noted that one AP is transmitting at 3 mW while the other is transmitting at 60 mW. How many decibels would the 3-mW AP need its power increased to match the 60- mW AP?
A. 8
B. 12
C. 13
D. 20
E. 57

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6 thoughts on “How many decibels would the 3-mW AP need its power increased to match the 60- mW AP?

  1. Easiest way here is simply how to get from 3 to 60? Multiply 3 by ten then double it. That is 3 x 10 x 2 = 60.
    In dB multiply by 10 = +10dB. Then double + +3 dB. 10 + 3 + 13.

  2. We need to use the 10db and 3db rules to get from 3mW to 60mW.

    10db = 10x, so 3mW + 10db = 30mW

    10x more would be too much, so we go to 3db.

    3db = 2x, so 30mw + 3db = 60mW

    Adding 10db gets you 10x the amount. Adding 3db gets you 2x the amount. Conversely, -10db is 1/10th and -3db is 1/2.

  3. i really would love to have an explanation for this question as i can’t find the result make sense

    1. Fox is right… add his 10dbm + 3dbm = 13db

      also

      3mw going to 60mw

      using 3dB * 2

      3mw * 2 = 6mw so we note the first 3dbm
      6mw*2 = 12mw so we note the second 3dbm but this time add the previous 3 = 6dbm
      12mw*2=24Mw so we note the third 3db + the previous 6dbm = 9dbm
      24mw*2= 48mw so we note the fourth 3db + previous 9dbm = 12dbm

      But now we cant multiply 48*2 since it will be more than 60mw so we subtract. 60mw -48mw = 2mw which is clode to 1db

      so 12 + 1 = 13 dbM

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