What are two possible results when two hosts in the vSAN cluster fail permanently?

A vSAN 5-node cluster has two sets of VMs, each associated with a separate storage policy.
-Group A (Storage Policy: FTT=0)
-Group B (Storage Policy: FTT=2)
What are two possible results when two hosts in the vSAN cluster fail permanently? (Choose two.)
A. VMs in Group B will become inaccessible if a third host permanently fails.
B. vSAN will rebuild data associated with Group A.
C. VMs in Group A might experience data inaccessibility.
D. VMs in Goup B might experience data loss.
E. A host can be put into maintenance mode without impacting VMs in either Group A or B.

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3 thoughts on “What are two possible results when two hosts in the vSAN cluster fail permanently?

  1. C is correct and Scot explained why. 5 nodes & fft=2 means RAID1. With RAID1 and FTT=2 you have one active disk and 2 replicas. So if we hit the worst case scenario where 2 copies are gone you will have ongoing rebuild/resync and one active object on the the remaining 3 hosts. If the rebuild is not over and we have 3rd host failure with the last remaining object on it the game is over, but if the object is on the other hosts we are still in the game so A is incorrect unless the question is asked in different way like”VMs in Group B could become ” And although didn’t test this I am completely sure that we can put one host in MM, the data from FFT=0/2 will/can be migrated to the remaining 2.

  2. AC

    Some of the VMs are not protected against a host failure (FTT=0), so if their replicas were on the failed hosts’ disks, you lost access to data. So C is correct.

    Some of the VMs were protected against the loss of 2 hosts (FTT=2). If you lose 3 hosts, game over. So A is correct.

    There’s no way to rebuild data if your FTT=0 and hosts fail. There’s no online copy of the data from which to rebuild.

    D is wrong because FTT=2 means you can tolerate 2 failures

    You can’t put a host in maintenance mode at this point without affected Group B and more of Group A. You’re effectively introducing a 3rd failure. So, E is wrong.

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