Refer to the exhibit. What is the most appropriate summarization for these routes?
A. 10.0.0.0 /21
B. 10.0.0.0 /22
C. 10.0.0.0 /23
D. 10.0.0.0 /24
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Thanks Dhanushka.
We need to summarize 4 subnets so we have to move left 2 bits (22 = 4). In this question we can guess the initial subnet mask is /24 because 10.0.0.0, 10.0.1.0, 10.0.2.0, 10.0.3.0 belong to different networks. So “/24″ moves left 2 bits -> /22.
10.0.0.0/24 —— 10.0.00000000.0
10.0.1.0/24 —— 10.0.00000001.0
10.0.2.0/24 —— 10.0.00000010.0
10.0.3.0/24 —— 10.0.00000011.0
we can write it as;
10.0.000000xx.0 ———–
———————————————————————————-
10 = 00001010
0 = 00000000
———————————————————————————–
>>> 00001010.00000000.000000xx.00000000
==== we get 22 bits before x
———————————————————————————-
so we can write it as;
10.0.0.0/22