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Which of the following is a valid host IPv6 address? (Choose all that apply.)
A. ff02:a:b:c::l/64
B. 2001:aaaa: 1234:456c: 1/64
C. 2001:000a:lb2c::/64
D. 2fff:f:f:f::f/64
E. ff02:33ab:l:32::2/128
F. 2001:bad:2345:a:b::cef/128
Correct Answer: BF
Explanation/Reference:
Explanation:
Option B is valid, assuming theres a faulty colon : in the IPv6 Address, just before the last 1, that is: 2001:aaaa:1234:456c::1/64Option F is valid, dispite its odd network mask (128 bits), sometimes used in tunnel links.
Incorrect-answer:
Option A is invalid, since it is a Multicast addressOption C seems to be invalid because the 3rd group of characters includes an l (lb2c), but if it is a 1 instead of an l
(faulty scan) and the required options are 3 instead of 2, then this address is still valid (2001:000a:1b2c::/64), because the 4th group of characters would be 0000
(remember that we can represent a continuous sequence of zeros by ::).Option D is definitely invalid since it is a reserved address. As states the IANA online
:document about the IPv6 Unicast Global Addresses, the range below is reserved, not allocated to any RIR (Regional Internet Registry):
2E00:0000::/7 IANA 1999-07-01 RESERVED
F correct
And /64 does not represent a host… B seems definitely not a right answer
why you are assuming there is a faulty colon? if there is no colon in the test – address is not valid period.