Refer to the exhibit. Given the output from the show ip eigrp topology command, which router is the feasible successor?
router# show ip eigrp topology 10.0.0.5 255.255.255.255
IP-EIGRP topology entry for 10.0.0.5/32 State is Passive, Query
origin flag is 1, 1 Successor(s), FD is 41152000
A. 10.1.0.1 (Serial0), from 10.1.0.1, Send flag is 0x0
Composite metric is (46152000/41640000), Route is Internal
Vector metric:
Minimum bandwidth is 64 Kbit
Total delay is 45000 Microseconds
Reliability is 255/255
Load is 1/255
Minimum MTU is 1500
Hop count is 2
B. 10.0.0.2 (Serial0.1), from 10.0.0.2, Send flag is 0x0
Composite metric is (53973248/128256), Route is Internal
Vector Metric:
Minimum bandwidth is 48 Kbit
Total delay is 25000 Microseconds
Reliability is 255/255
Load is 1/255
Minimum MTU is 1500
Hop count is 1
C. 10.1.0.3 (Serial0), from 10.1.0.3, Send flag is 0x0
Composite metric is (46866176/46354176), Route is Internal
Vector metric:
Minimum bandwidth is 56 Kbit
Total delay is 45000 microseconds
Reliability is 255/255
Load is 1/255
Minimum MTU is 1500
Hop count is 2
D. 10.1.1.1 (Serial0.1), from 10.1.1.1, Send flag is 0x0
Composite metric is (46763776/46251776), Route is External
Vector metric:
Minimum bandwidth is 56 Kbit
Total delay is 41000 microseconds
Reliability is 255/255
Load is 1/255
Minimum MTU is 1500
Hop count is 2
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For a route to be chosen as a feasible successor, one condition must be met:
the neighbor’s advertised distance (AD) for the route must be less than the successor’s feasible distance (FD).
EIGRP is a distance vector routing protocol, so B – HOP count is 1