An 802.11n implementation is being discussed. Users are satisfied with the potential 300- 450 Mbps throughput of new 802.11n APs.
Which three bandwidth requirements are used to calculate per client bandwidth through an 802.11 n AP network? (Choose three.)
A. 450 Mbps throughput is the client max for 5-GHz radio.
B. Channel bonding on 5 GHz is required for a client to have a 300 Mbps WiFi link.
C. 300 Mbps throughput is the client max for 2.4-GHz radio.
D. The remaining bandwidth is divided per device when more clients are connected to one AP.
E. 100 Mbps Ethernet switch port is a potential bottleneck.
F. CleanAir helps clear noise for 802.11n channel bonding to work.
ABE
Stupid answers! No 300Mbps is not hte max for a 2.4GHz client! if using MCS23 with 40MHz and with 3spatial stream, it will also be able to get 450Mbps!
the proof here a TPlink router doing only 802.11bgn and able to provide 450Mbps:
https://fr.aliexpress.com/item/TP-LINK-WiFi-Roteador-Wireless-Home-Router-TP-LINK-802-11n-450Mbps-Wi-Fi-Repeater-TPlink/32259468777.html
So, A is true even if not especially on 5GHz.
B is also true even if not especially on 5GHz. Channel bonding is also required on 2.4GHz for getting 300Mbps (MCS15) !
And then D is true by design we have shared bandwidth per time of access.
E&F looks more like remarks to pay attention but nothing directly related to the client bandwidth question.
BDE
ACD