A 802.11n implementation is being discussed. Users are satisfied with the potential 300- 450 Mbps throughput of new 802.11n APs. Which three bandwidth requirements are used to calculate per client bandwidth through an 802.11n AP network? (Choose three.)
A. 300 Mbps throughput is the client max for 2.4-GHz radio.
B. 450 Mbps throughput is the client max for 5-GHz radio.
C. 100 Mbps AP Ethernet switch port is a potential bottleneck.
D. CleanAir helps clear noise for 802.11n channel bonding to work.
E. Channel bonding on 5 GHz is required for a client to have a 300 Mbps WiFi link.
F. The remaining bandwidth is divided per device when more clients are connected to one AP.
B,C,F
https://www.centurylink.com/home/help/internet/wireless/which-frequency-should-you-use.html
CEF is correct
A) I’d not recommend channel bonding on 2.4 GHz, so max for 20 MHz channels is 288.9 Mbps, with channel bonding 600 Mbps
B) Max. is 600 Mbps
C) Correct, 2 ss + 20 MHz channel gives 144.4 Mbps. So a 100 Mbps is a bottleneck
D) it doesn’t clean the air, it helps to avoid channels that are ‘dirty’
E) 300 Mbps can only be reach with 40 MHz channels
F) Wi-Fi is a shared medium, so yes you divide the bandwidth.
http://mcsindex.com/
I Agree
I agree, too
Agree, Max 300 Mbit/s can be achieved on 2 SS for 40 Mhz change bonding.
C.F logical, no comment requires
A,B,F I think?