P has one abstract method –> functional interface
Q extends P and override the method1 so Q has 1 abstract function –> functional interface
R extends P but has another method so R has 2 methods (method1 and method2) –> not functional interface
T,U have 2 abstract functions –>not functional interface
C and E are correct because Q extends P the methods are the same therefore Over Ridding end up having a Functional interface
C and E
P has one abstract method –> functional interface
Q extends P and override the method1 so Q has 1 abstract function –> functional interface
R extends P but has another method so R has 2 methods (method1 and method2) –> not functional interface
T,U have 2 abstract functions –>not functional interface
so P & Q —> answer C,E
Sorry, but why ??
P and Q