Which two statements about EUI-64 addressing are true? (Choose two.)
A. The address includes the hex digits FFFE after the last 24 bits of the interface MAC address.
B. A 64-bit interface identifier is derived from the interface MAC address.
C. A locally administrated address has the universal/local bit set to 0.
D. A 96-bit interface identifier is derived from the interface MAC address.
E. The address includes the hex digits FFFE after the first 24 bits of the interface MAC address.
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The answer should be B & E.
0 for universal and 1 for local.
its C & E
C is wrong
https://ccie20728.wordpress.com/2008/12/18/ipv6-universallocal-bit/
The link you provided made c one of the answers – local administered has the u/l bit set to 0, universal is 1
Think the answer should be C & E
16-bit 0xFFFE is inserted between these two 24-bits for the 64-bit EUI address.
Next, the seventh bit from the left, or the universal/local (U/L) bit, needs to be inverted. This bit identifies whether this interface identifier is universally or locally administered. If 0, the address is locally administered and if 1, the address is globally unique
BE – correct
E is correct. B is also correct answer. What is the meaning of C?
the answer should be C & E.
Pls explain the meaning of statement made in C
FFFE is in the middle – “E” is the correct answer.
“B” is correct – 64-bit interface identifier is derived from the interface MAC address.
“C” is NOT correct because is “1” not “0”.
A locally administrated address has the universal/local bit set to 1.
The Answer should be B & E
Agree, the answer should be C & E
The Answer should be C & E. FFFE comes in the middle.