Which two statements are true about 6to4 tunneling? (Choose two)
A. It works by appending the public lPv4 address (converted into hexadecimal format) to the 2002::116 prefix
B. It embeds the lPv6 packet into the lPv4 payload with the protocol type set to 51.
C. It works by appending the private lPv4 address (converted into hexadecimal format) to the 2002::/16 prefix.
D. It embeds the lPv6 packet into the lPv4 payload with the protocol type set to 41.
C & E should be the correct – https://en.wikipedia.org/wiki/6to4
ok… I get the point: C can’t be correct, as it says ‘private’ ipv4 address, while 6to4 uses public ipv4 addresses. So I guess A is correct, but there’s a typo there >>> instead of 2002::/16, they wrote 2002::116.
Yes… I Agree. Typo