Given:
What is the result?
A. false
salesquarter . . qtrlreport.txt
B. false
quarter . . qtrlreport.txt
C. true
. . . . . . annualreport.txt
D. true
. . . . annualreport.txt
Correct Answer: A
Explanation/Reference:
Explanation:
( richtig !! import java.nio.file.Path; import java.nio.file.Paths; ) original-Aufgabe war ( falsch >> import java.io.file.Path; import java.io.file.Paths; )
The relativize method that can be used to construct a relative path between two paths. relativize
Path relativize(Path other)
Constructs a relative path between this path and a given path.
Parameters: other – the path to relativize against this path
Returns: the resulting relative path, or an empty path if both paths are equal
Note:
Relativization is the inverse of resolution. This method attempts to construct a relative path that when resolved against this path, yields a path that locates the same file as the given path. For 18 example, on UNIX, if this path is "/a/b" and the given path is "/a/b/c/d" then the resulting relative path would be "c/d". Where this path and the given path do not have a root component, then a relative path can be constructed. A relative path cannot be constructed if only one of the paths have a root component. Where both paths have a root component then it is implementation dependent if a relative path can be constructed. If this path and the given path are equal then an empty path is returned.
For any two normalized paths p and q, where q does not have a root component, p.relativize(p.resolve(q)).equals(q)
When symbolic links are supported, then whether the resulting path, when resolved against this path, yields a path that can be used to locate the same file as other is implementation dependent. For example, if this path is "/a/b" and the given path is "/a/x" then the resulting relative path may be "../x". If "b" is a symbolic link then is implementation dependent if "a/b/../x" would locate the same file as "/a/x".
Explanation/Reference:
Explanation:
( richtig !! import java.nio.file.Path; import java.nio.file.Paths; ) original-Aufgabe war ( falsch >> import java.io.file.Path; import java.io.file.Paths; )
The relativize method that can be used to construct a relative path between two paths. relativize
Path relativize(Path other)
Constructs a relative path between this path and a given path.
Parameters: other – the path to relativize against this path
Returns: the resulting relative path, or an empty path if both paths are equal
Note:
Relativization is the inverse of resolution. This method attempts to construct a relative path that when resolved against this path, yields a path that locates the same file as the given path. For 18 example, on UNIX, if this path is "/a/b" and the given path is "/a/b/c/d" then the resulting relative path would be "c/d". Where this path and the given path do not have a root component, then a relative path can be constructed. A relative path cannot be constructed if only one of the paths have a root component. Where both paths have a root component then it is implementation dependent if a relative path can be constructed. If this path and the given path are equal then an empty path is returned.
For any two normalized paths p and q, where q does not have a root component, p.relativize(p.resolve(q)).equals(q)
When symbolic links are supported, then whether the resulting path, when resolved against this path, yields a path that can be used to locate the same file as other is implementation dependent. For example, if this path is "/a/b" and the given path is "/a/x" then the resulting relative path may be "../x". If "b" is a symbolic link then is implementation dependent if "a/b/../x" would locate the same file as "/a/x".
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