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What number of IOPS should be used with Storage I/O Control to limit disk throughput to roughly 10 MBps if the guest application writes 64KB blocks?
A. 320
B. 160
C. 240
D. 64
Correct Answer: B
Explanation/Reference:
Kbps devided by Block Size
There are 1024 Kb in a Mb so you would convert the 10 Mbps to Kbps. Then divide the result by the block size being used: 64.
1024 x 10=10240 Kbps
10240 / 64=160 IOPs
There’s a variation on this:
What number of IOPS should be used with Storage I/O Control to limit disk throughput to roughly 15 MBps if the guest application writes 64KB blocks?
1024 x 15 = 15360
15360 / 64 = 240
