A company plans to deploy a new application in their environment. The new application requires 2 TB of storage space. During peak workloads, the application is expected to generate 4500 IOPS with a typical I/O size of 4 KB. The capacity of each available disk drive is 250 GB. In addition, the maximum number of IOPS a drive can perform at with a 70% utilization is 90 IOPS.
What is the minimum number of disk drives needed to meet the application’s capacity and performance requirements for a RAID 0 configuration?
A. 8
B. 40
C. 50
D. 70
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I think the answer should be C, since 90 IOPS is already 70% utilization.
• D. 70 (4500/90IOPS – 50 *25% -> 70)
should consider 25%
Hi Jensen
Please explain the scenario, answer
will be helpful to understand.
Thank you
4500IOPS / 90IPS(per 1drive) = 50 drivers
50 drives * 250GB = 62500GB > 2TB (utilization 30%, this is under 70%)
answer is “C”
Hmm,
4500iops/90iops = 50 disks
50*250GB = 12500 gb
(12500gb * 0.7)/1000 = 8.75 TB which is > 2 TB , utilization is 2/12.5 * 100(%) = 16% os is < 70%
C：50