Refer to the exhibit. The router has been configured with these commands:
hostname Gateway interface FastEthernet 0/0 ip address 198.133.219.14 255.255.255.248 no shutdown interface FastEthernet
0/1 ip address 192.168.10.254 255.255.255.0 no shutdown interface Serial 0/0
ip address 64.100.0.2 255.255.255.252 no shutdown
ip route 0.0.0.0 0.0.0.0 64.100.0.1
What are the two results of this configuration? (Choose two.)
A. The default route should have a next hop address of 64.100.0.3.
B. Hosts on the LAN that is connected to FastEthernet 0/1 are using public IP addressing.
C. The address of the subnet segment with the WWW server will support seven more servers.
D. The addressing scheme allows users on the Internet to access the WWW server.
E. Hosts on the LAN that is connected to FastEthernet 0/1 will not be able to access the Internet without address translation.
I think D&E is correct:
A. False – Gateway of last resort is 64.100.0.1
B. False – 192.168.10/24 is directly connected, FastEthernet 0/1
C. False – /29 address allows 8 addresses per network with 6 usable. 1 host is already used, leaving 5 remaining
D. True – Assume relevant routing is correct
E. True – NAT overload required
Correct answer is BD. If hosts on the FastEthernet 0/1 are using public address then they don’t need NAT to access the Internet so E is wrong.
the 198 network is configure on the fast e 0/0 D&E are correct