Which combination of values is valid for a router-on-a-stick implementation?
A. IP address 173.15.20.6/20, gateway 173.15.30.1, and VLAN 20
B. FastEhernet interface 0/0.30, IP address 173.15.20.33/27, gateway 173.15.20.1 and VLAN 30
C. IP address 173.15.30.6/26, gateway 173.15.30.62, and VLAN 20
D. FastEthernet interface 0/0.20, IP address 173.15.30.33/27, gateway 173.15.30.1 and VLAN 30
C is the correct answer.
128 64 32 16 8 4 2 1 . 128 64 32 16 8 4 2 1
| | | | 0 0 0 0 . 0 0 0 0 0 0 0 0
2 4 8 16 32 64 128 256 512 1024 2048 4096
Network Range Broadcast
0 (0.1 – 15.254) 15.255
16 (16.1 – 31.254) 31.255 173.15.20.6/20 & 173.15.30.1
32 (32.0 – 47.254) 47.255
48
128 64 32 16 8 4 2 1 . 128 64 32 16 8 4 2 1
| | | | | | | | . | | 0 0 0 0 0 0
2 4 8 16 32 64 128 256
Network Range Broadcast
0 (1 – 62) 63 173.15.30.6/26 & 173.15.30.62 = Last Of usable Range
64
128
192
256
Agreed A and C will work but (C) is the most efficient and wastes less ip addresses.
Both A and C are correct answers. Subletting question can really tax your head for no good reason (LOL).