Which of the following are valid host addresses for the subnet 203.0.113.64/28? (Choose two.)
A. 203.0.113.64
B. 203.0.113.78
C. 203.0.113.65
D. 203.0.113.80
E. 203.0.113.81
Which of the following are valid host addresses for the subnet 203.0.113.64/28? (Choose two.)
A. 203.0.113.64
B. 203.0.113.78
C. 203.0.113.65
D. 203.0.113.80
E. 203.0.113.81
with /28 subnet we will have a block size of 16 between each network:
203.0.113.0 ==> hosts (from 203.0.113.1 to 203.0.113.14)
203.0.113.16 ==> hosts (from 203.0.113.17 to 203.0.113.30)
.
.
203.0.113.64 ==> hosts (from 203.0.113.65 to 203.0.113.78) <== this network contains both .65 and .78 hosts
203.0.113.80
Thus, B&C
the correct answer is B and C.
/28 = 16 bits for the hosts
= 16 adresses -2 (network + broadcast)
= 14 available hosts.
hostMin = 1
hostMax = 14
I meant: /28 = 4 bits remaining for the hosts that equals 16 adresses.
/28 = 255.255.255.240 = 7 ip´s
only C
ops = 15 ip´s validos, B e C mesmo