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If X is a positive integer and (405) 4 is a multiple of 3X, what is the largest possible value of X?
A. 5.
B. 12.
C. 16.
D. 20
E. 26.
Correct Answer: C
Explanation/Reference:
Explanation:
Find the factors of (405) 4 and see what the largest value of X can be. 405 = 81 x 5 = 9 x 9 x 5 = 3 x 3 x 3 x 3 x 5 – (405) 4 = (3 x 3 x 3 x 3 x 5) 4 = 316 x 54. The largest possible value of 3X that is still a factor of (405) 4 is the largest possible value of X and that is 316. X = 16. The correct answer is C.
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