The chance of a hard drive failure is known to be once every four years. The cost of a new hard drive is $500. EF (Exposure Factor) is about 0.5. Calculate for the Annualized Loss Expectancy (ALE).

10 thoughts on “The chance of a hard drive failure is known to be once every four years. The cost of a new hard drive is $500. EF (Exposure Factor) is about 0.5. Calculate for the Annualized Loss Expectancy (ALE).”

1. ALE is Annual loss expectancy not a loss for four years

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2. A…

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3. My advice is to,watch this two min video on 312-50

   https://youtu.be/2Nlpmp8uJfE

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4. A. $62.5

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5. The answer is A. The life expectancy is 4 years but when you calculate the ALE, it should be calculated on a yearly basis, thus ALO = 1/4 = 0.25

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6. 1/4=0.25

   0.25*500*0.5= 62.5

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7. My friend you calculated for one year 62.5 see questions he is asking about 04 years

   62.5 X 4 = 250

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8. i think the answer is A, isn’t it?

   ALE=SLE*ARO
   SLE=AV*EF

   so, ALE = AV*EF*ARO = 500*0.5*0.25=62.5…

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   1. I agree with you:

      https://en.wikipedia.org/wiki/Annualized_loss_expectancy

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   2. I agree too, I think the answer should be A

      Assign a value for the annualized rate of occurrence (ARO)—The ARO represents the estimated frequency at which a given threat is expected to occur. Simply stated, how many times is this expected to happen in one year?

      Refer to http://www.pearsonitcertification.com/articles/article.aspx?p=728428&seqNum=4

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