What is the approximate cost of replacement and recovery operation per year of a hard drive that has a value of $300 given that the technician who charges $10/hr would need 10 hours to restore OS and Software and needs further 4 hours to restore the database from the last backup to the new hard disk? Calculate the SLE, ARO, and ALE. Assume the EF = 1 (100%).
A. $440
B. $100
C. $1320
D. $146
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Since you are not replacing every year, the cost total cost is spread out over the 3 years. $440 x 1/3 = $146 (approx)
Gosh… Finally! No wonder I stared at the question so hard and trying to decipher where did the info on 0.33 comes about! Thank you so much!
The answer to this question as it is formulated is A: $440 but it seems there is a missing part.
Here is the actual question:
The chance of a hard drive failure is once every three years. The cost to buy a new hard drive is $300. It will require 10 hours to restore the OS and software to the new hard disk. It will require a further 4 hours to restore the database from the last backup to the new hard disk. The recovery person earns $10/hour. Calculate the SLE, ARO, and ALE. Assume the EF = 1 (100%). What is the closest approximate cost of this replacement and recovery operation per year?
There is missing the part that the replacement takes place every 3 years.
So the formula goes like:
[300 + 10 * (10 + 4)] * 1 = 440
Then:
440 / 3 = 146.6
If the replacement takes place every 4 years just do 440 / 4.
how ARO = 0.33 THERE is no info about it ?
Well, according to the question the correct answer is A. $440.
The question didn’t mention 3 or 4 year replacement, it mentions about “per year” replacement.
I agree with your analysis and believe the answer is A.
Annual rate of occurrence (ARO) is 0.33. Single loss expectancy (SLE) is $300 + (14 * $10) = $440. The Annual loss expectancy (ALE) = ARO * SLE = $145.2
This is not a complete question.