A network administrator has subnetted the 172.16.0.0 network using a subnet mask of 255.255.255.192. A duplicate IP address of 172.16.2.120 has accidentally been configured on a workstation in the network. The technician must assign this workstation a new IP address within that same subnetwork. Which address should be assigned to the workstation?
A. 172.16.1.80
B. 172.16.2.80
C. 172.16.1.64
D. 172.16.2.64
E. 172.16.2.127
F. 172.16.2.128
Assuming you used pen and paper, but use the very excellent calc (http://subnettingpractice.com/calc.html) to confirm.
The network address is 172.16.2.64, so not D. The next available network address is 172.16.2.128, so not F.
The broadcast address is 172.16.2.127, so not E.
The valid host range is 172.16.2.65 to 172.16.2.126, so not A or C.
B is the only address that falls in the host range.
Correct – 172.16.2.65 – 172.16.2.126 will be valid, so D. 172.16.2.64 is correct