Refer to the exhibit. HostA cannot ping HostB. Assuming routing is properly configured, what is the cause of this problem?
A. HostA is not on the same subnet as its default gateway.
B. The address of SwitchA is a subnet address.
C. The Fa0/0 interface on RouterA is on a subnet that can’t be used.
D. The serial interfaces of the routers are not on the same subnet.
E. The Fa0/0 interface on RouterB is using a broadcast address.
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Bogart, you are wrong!
Both interfaces on Router A are supposed to be on different subnets – it’s ESSENTIAL for the routing process. Each “leg” should connect to a different network/subnetwork.
Let’s simplify this by analyzing each possible answer:
A. Host A is not on the same subnet as its default gateway.
– False: the subnet address is 192.168.1.32 and it goes till the next one 192.168.1.64 – so both host A and the DG are on the same subnet.
B. The address of Switch A is a subnet address.
– False: The management IP address of switch A has nothing to do with the routing of the packets. The switch operates on L2.
C. The Fa0/0 interface on Router A is on a subnet that can’t be used.
– False: f0/0 has the IP address 192.168.1.33 /27 – hence the subnet address, as explained earlier is 192.168.1.32. The interface has a valid address.
D. The serial interfaces of the routers are not on the same subnet.
– True: Interface S0/0 on Router A belongs to the 192.168.1.32 subnet, and S0/0 on Router B belongs to the 192.168.1.64 subnet. They wouldn’t be able to communicate with each other.
E. The Fa0/0 interface on Router B is using a broadcast address.
– False: Since it’s a /27 network, the hop-count is of 32. The next subnet after 192.168.1.64 is 192.168.1.96, so fa0/0 on Router B belongs to this subnet and does not have a subnet address.
Hope this clarifies everything. This is a very basic subnetting question.
Totally I agree with you Bogart…
Is this a valid Q? Look at the ip address of S0/0 and F0/0 on Router A they are on the same subnet. The router will not accept the IP address if you will configure it.